Question

resolva as equações: a) 3x + 1 = 10

b) 9x = 4x - 5
c) 5 = 4x - 3
d) 18x = 36 + 6x
e) 8x - 16 = 4x - 16

Answer 1

✔OLÁ!!!

$a)3x + 1 = 10 \\ 3x = 10 - 1 \\ 3x = 9 \\ x = \frac{9}{ 3} \\ x = 3$

$b)9x = 4x - 5 \\ 9x - 4x = 5 \\ 5x = -5 \\ x = -\frac{5}{5} \\ x = -1$

$c)5 = 4x - 3 \\ - 4x = - 3 - 5 \\ - 4x = - 8( - 1) \\ 4x = 8 \\ x = \frac{8}{4} \\ x= 2$

$d)18x = 36 + 6x \\ 18x - 6x = 36 \\ 12x = 36 \\ x = \frac{36}{12} \\ x = 3$

$e)8x - 16 = 4x - 16 \\ 8x - 4x = - 16 + 16 \\ 4x = 0 \\ x = \frac{0}{4} \\ x = 0$

Answer 2

a) 3x + 1 = 10

3x = 10 - 1

3x = 9

x = 9/3

x = 3

b) 9x = 4x - 5

9x - 4x = -5

5x = -5

x = -5/5

x = -1

c) 5 = 4x - 3

-4x = - 3 - 5

-4x = -8 .(-1)

4x = 8

x = 8/4

x = 2

d) 18x = 36 + 6x

18x - 6x = 36

12x = 36

x = 36/12

x = 3

e) 8x - 16 = 4x - 16

8x - 4x = -16 + 16

4x = 0

x = 0/4

x = 0