Question

Resolva as equações A)2×-7/5=8×-31/5
B)4×-7/3=5×/3
C)5×-1/18=11-×/18
D)3×/5+4/3=×10
E)×/6+1/12=1/4
F)×/6-1/3=1/2
G)×+×/3=8
H)×/3-1×/4

POR FAVOR EU PRECISO DO CALCULO COM AS RESPOSTAS MUITO OBRIGADO(A) POR MIM AJUDAR

Answer 1

a)

$2x- \frac{7}{5} =8x- \frac{31}{5}$

Agrupar os termos semelhantes (lembrar de trocar o sinal quando passar um termo para o outro lado da igualdade):

$2x-8x=- \frac{31}{5} + \frac{7}{5}$

m.m.c. = 5

$-6x= \frac{-31+7}{5}$

$-6x= -\frac{24}{5}$ (-1) multiplicar por -1 para positivar

$6x = \frac{24}{5}$

$x= \frac{6.24}{5}$

$x= \frac{144}{5}$

b)

$4x- \frac{7}{3} = \frac{5x}{3}$

$4x- \frac{7}{3} - \frac{5x}{3} =0$

m.m.c.= 3

$\frac{12x-7-5x}{3} =0$

7x - 7 = 3

7x = 3 + 7

7x = 10

$x= \frac{10}{7}$

c)

$5x- \frac{1}{18} =11- \frac{x}{18}$

$5x- \frac{1}{18} -11+ \frac{x}{18} =0$

m.m.c. = 18

$\frac{90x-1-198+x}{18} =0$

91x - 199 = 18

91x = 18 + 199

91x = 217

$x= \frac{217}{91}$

d)

$\frac{3x}{5} + \frac{4}{3} =10x$

$\frac{3x}{5} + \frac{4}{3} -10x=0$

m.m.c.=15

$\frac{9x+20-150x}{15} =0$

9x - 150x = 15 - 20

-141x = -5 (-1)

141x = 5

$x= \frac{5}{141}$

e)

$\frac{x}{6} + \frac{1}{12} = \frac{1}{4}$

$\frac{x}{6} + \frac{1}{12} - \frac{1}{4} =0$

m.m.c.=12

$\frac{2x+1-3}{12} =0$

2x + 1 - 3 = 12

2x = 14

$x= \frac{14}{2}$

x = 7

f)

$\frac{x}{6} - \frac{1}{3} = \frac{1}{2}$

$\frac{x}{6} - \frac{1}{3} - \frac{1}{2} =0$

m.m.c.= 6

$\frac{x-2-3}{6} =0$

x - 2 - 3 = 6

x = 6 + 2 + 3

x = 11

g)

$x+ \frac{x}{3} =8$

$x+ \frac{x}{3} -8=0$

m.m.c.= 3

$\frac{3x+x-24}{3} =0$

4x - 24 = 3

4x = 3 + 24

4x = 27

$x=\frac{27}{4}$

h)

$\frac{x}{3} -1= \frac{x}{4}$

$\frac{x}{3} -1- \frac{x}{4} =0$

m.m.c.=12

$\frac{4x-12-3x}{12} =0$

x - 12 = 12

x = 12 + 12

x = 24