Question

Resolva as equações:

A: 12+16:8x3-5 =
B: (4+2x5)-3=
C: 82-8x7:(4-1x3)=
D: 25-[10-(2x3+1)]=
E: 8:2+[15-(4x2+1)]=
F: 9+[4+2x(6-4)+(2+5)]-8=
G: 50+{10-2x[(6+4:2)-(10-3)]}=
H: 180:{10+2x[20-45:(13-2x5)]}=
I: (5+3x2)-1=
J: 25+(8:2+1)-1=
K: [40+2x(7-5)]x2-20=
L: 90-[25+(5x2-1)+3]=
M: 50-2x{7+8:2-[9-3x(5-4)]}=
N: [(4+16.2) . 5-10] .100=
O: { 10+[5.(4+2.5)-8].2}-100=
P: 80-5.(28-6.4)+6-3.4=
Q: [6.(3.4-2.5)-4]+3.(4-2)-(10:2)=
R: 67+{50.[70:(27+8)+18:2] +21}=

Answer 1

A: 12+16:8x3-5 =
12+2x3-5=
12+6-5= 13

B: (4+2x5)-3=
(4+10)-3=
14-3=11

C: 82-8x7:(4-1x3)=
82-56:(4-3)=
82-56:1=
82-56=26

D: 25-[10-(2x3+1)]=
25-[10-7]=
25-[3]=
25-3=22

E: 8:2+[15-(4x2+1)]=
4+[15-(9)]=
4+15-9=10

F: 9+[4+2x(6-4)+(2+5)]-8=
9+[4+12-8+2+5]-8=
9+[17]-8=18


G: 50+{10-2x[(6+4:2)-(10-3)]}=
50+[10-2x(6+2)-10+3]=
50+[10-16-10+3]=
50-13=37

H: 180:{10+2x[20-45:(13-2x5)]}=
180÷{10+2x[20-45÷(13-10)]}=
180{{10+2x[20-45÷3]}=
180÷{10+2x[20-15]}=
180÷{[10+2x5}=
180÷{10+10}=
180÷20=9

I: (5+3x2)-1=
(5+6)-1
11-1=10

J: 25+(8:2+1)-1=
25+(4+1)-1=
25+5-1=29

K: [40+2x(7-5)]x2-20=
[40+2x2]x2-20=
[40+4]x2-20=
44x2-20=
88-20=68

L: 90-[25+(5x2-1)+3]=
90-[25+9+3]=
90-37=53

M: 50-2x{7+8:2-[9-3x(5-4)]}=
50-2x{7+4-[9-15+12]}=
50-2x{7+4-[6]}=
50-2x{5}=
50-10=40

N: [(4+16.2) . 5-10] .100=
[(4+32).5-10].100=
[36.5-10].100=
[180-10].100=
170.100=17000

O: { 10+[5.(4+2.5)-8].2}-100=
{20+[5.14-8].2}-100=
{20+[70-8}.2-100=
{20+[62.2-100=
{20+124-100}=
144-100= 44

P: 80-5.(28-6.4)+6-3.4=
80-5.(28-24)+6-12=
80-5.4-6=
80-20-6=
60-6=54

Q: [6.(3.4-2.5)-4]+3.(4-2)-(10:2)=
[6.(12-10)-4]+12-6-5=
[6.2-4]+1=
12-4+1=
8+1=9

R: 67+{50.[70:(27+8)+18:2] +21}=
67+[50.[70:35+9]+21=
67+[50.[2+9]+21=
67+[50.11]+21=
67+550+21=638

Boa sorte. se errar no cálculos de alguma, desculpe, foram muitas e extensas. Estou em celular.