Question

Resolva as equações.

Answer 1

$\frac{x-1}{4} - \frac{2x-1}{3} = \frac{x}{12} \\ \\ 3(x-1)-4(2x-1)=x \\ \\ 3x-1-8x+4=x \\ \\ -5x-x=-4+1 \\ \\ -6x=-3 \\ \\ x= \frac{-3}{-6} = \frac{1}{2}$

$\frac{ (x-1)^{2} }{2} - \frac{x(x+1)}{3} = \frac{1}{2} \\ \\ 3( x-1)^{2} -2x(x+1)=3 \\ \\ 3( x^{2} -2x+1)-2 x^{2} -2x-3=0 \\ \\ 3 x^{2} -6x+3-2x^2-2x-3=0 \\ \\ x^2-8x=0 \\ \\ x(x-8)=0 \\ \\ x=0 \\ \\ x=8$