Question

resolva as equações 16x+2.(7x+8)-9=67 6.(4z+2)+7.(-5z+3)=66 27=3.(x+3) (7x-8).2=6.(3x-4) 16x-6-7x=15+2x

Answer 1

Primeira:
16x+2(7x+8)-9=67
16x+14x+16-9=67
16x+14x=67+9-16
30x=60
x=60÷30
x=2

Segunda:
6(4z+2)+7(-5z+3)=66
24z+12-35z+21=66
24z-35z=66-12-21
-11z=33
-z=33÷11
z=-3

Terceira:
27=3(x+3)
27=3x+9
27-9=3x
18=3x
18÷3=x
x=6

Quarta:
(7x-8)2=6(3x-4)
14x-16=18x-24
24-16=18x-14x
8=4x
x=8÷4
x=2

Quinta:
16x-6-7x=15+2x
16x-7x-2x=15+6
7x=21
x=3