Question

resolva as equações
1)x + 6 = 5
2)10 = x +
3)33 + x = 5 - 3x
4)35 x = - 105
5)7 Y - 10 = Y + 50
6)2(x-3)+8x+4=5(x+2)
7)5(2x menos 1) de qual 3 (x + 10)
com conta pfvr​

Answer 1

Resposta:

1) x = - 1

3) x = - 7

4) x = - 7

5) y = 10

6) x = $\frac{12}{5}$

7) x = 5

Explicação passo-a-passo:

1) x + 6 = 5

x = 5 - 6,    x = - 1

3) 33 + x = 5 - 3x

x + 3x = 5 -33

4x = - 28,     x = - 7

4) 35x = - 105

x = - $\frac{105}{35}$,       x = - 7

5) 7y - 10 = y + 50

7y - y = 50 + 10

6y = 60,       y = 10

6) 2(x - 3) + 8x + 4 = 5(x + 2 )

2x - 6 + 8x +4 = 5x +10

2x + 8x - 5x = 10 +6 - 4

5x = 12,       x = $\frac{12}{5}$

7) 5(2x - 1) = 3(x + 10)

10x - 5 = 3x + 30

10x - 3x = 30 + 5

7x = 35

x = 5