Matemática, perguntado por charmiris2010, 1 ano atrás

resolva as equação do 2° em IR

a) x²-25=0
b) 2x²-72=0
c) 7x²- 14=0
d) x² + 10=0
e) -64 + 4x²=0
f) 24=6x²
g) 64x²- 1=0
h) x²-81/4=0
i) x²- 90=31
j) x²- 200=200
k) 9x²=25 + 8x²
l) x²=99-10x²
m) 2x² + 11= x² + 12
n) 5(x²-1) =4 (x²+1)
o) x(x+2)= 2x + 24

Soluções para a tarefa

Respondido por alcon
0
a)x^2-25=0
x^2=25
x=+,-\/25
x+,-5

b)2x^2-72=0
2x^2=72
x^2=72/2
x^2=36
x+,-\/36
x=+,-6

c)7x^2-14=0
7x^2=14
x^2=14/7
x^2=2
x=+,-\/2
x=+,-1,41

d)x^2+10=0
x^2=10
x=+,-\/10
x=+,-3,16

e)-64+4x^2=0
4x^2=64
x^2=64/4
x^2=16
x=+,-\/16
x=+,-4

f)24=6x^2
x^2=24/6
x^2=4
x=+,-\/4
x=+,-2

g)64x^2-1=0
x^2=1/64
x=+,-\/1/64
x=+,-1/8

h)x^2-81/4=0
4x^2-81/4=0
4x^2=81(4)
x^2=81(4)/4
x^2=81
x=+,-\/81
x=+,-9

i)x^2-90=31
x^2=31+90
x^2=121
x=+,-\/121
x=+,-11

j)x^2-200=200
x^2=200+200
x^2=400
x=+,-\/400
x=+,-20

k)9x^2=25+8x^2
9x^2-8x^2=25
x^2=25
x=+,-5

l)x^2=99-10x^2
x^2+10x^2=99
11x^2=99
x^2=99/11
x^2=9
x=+,-\/9
x=+,-3

m)2x^2+11=x^2+12
2x^2-x^2=12-11
x^2=1
x=+,-\/1
x=+,-1

n)5(x^2-1)=4(x^2+1)
5x^2-5=4x^2+4
5x^2- 4x^2=4+5
x^2=9
x=+,-\/9
x=+,-3

o)x(x+2)=2x+24
x^2+2x=2x+24
x^2+2x-2x-24=0
x^2-24=0
x^2=24
x=+,\/24
x=+,\/4x6
x=+,-2\/6
x=+,-4,88
x^3



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