resolva as as expressões numéricas
a){[✓49+(2⁴-1)]•✓64}+✓1024=
b)-54:{(-2+✓81)²:7-[(-2³+✓4):3]}=
c)(-1/3)²-✓1/16•[3/4-(-3/2)²=
preciso de ajudaaaa por favor
Soluções para a tarefa
a){[✓49+(2⁴-1)]•✓64}+✓1024=
> √49 = 7
> 2⁴ = 2.2.2.2 = 16
> √64 = 8
> √1024 = 32
• {[ 7 + (16-1).8 + 32]} =
> 16-1 = 15
• {[ 7 + 15 . 8 +32]} =
> 15.8 = 120
• {[ 7+120+32]} =
• {[ 127+32]}
• 159 → Resposta
b)-54:{(-2+✓81)²:7-[(-2³+✓4):3]}=
> √81 = 9
> -2³ = -2×-2×-2 = -8
> √4 = 2
• -54:{(-2+9)²:7-[(-8+2):3]} =
> (-2+9) = 7
> (-8+2) = -6
• -54:{(7)²:7-[-6:3]} =
> (7)² = 7×7 = 49
> [-6:3] = [-2]
• -54{49:7-[-2]} =
> 49:7 = 7
• -54{ 7 -[-2]} =
> -[-2] = +2
• -54{7+2} =
• -54.+9 =
• -486 → Resposta
c)(-1/3)²-✓1/16•[3/4-(-3/2)²]=
> (-1/3)² = (-1/3).(-1/3) = 1/9
> √1/16 = 1/4....pq ,1/4×1/4 = 1/16
> (-3/2)² = 9/4 ....pq , (-3/2).(-3/2) = 9/4
• 1/9 -1/4. [3/4 -(+9/4) ]=
> -(+9/4) = -9/4
• 1/9-1/4.[3/4-9/4] =
> 3/4-9/4 = -6/4
• 1/9-1/4 . -6/4
> -1/4.-6/4 = -1.-6/4.4 = 6/4
• 1/9 +6/16
> m.m.c de 9 e 16 = 144
• 16/144+9/144
> 16/144+9/144 = 25/144
• 25/144 → Resposta
Espero ter ajudado...obgd..