Question

resolva aplicando as propriedades da potência a) (0,2)^5 .(0,2)⁴. (0,2)³:(0,2)^9=

b) (0,01)^5:(0,01)³=

c)3²+(3³:3²)=

Answer 1

$a)\ ( 0,2)^{5} . (0,2)^{4} . (0,2)^{3} : (0,2)^{9} = 0,2^{5+4+3-9} = 0,2^{9-6} =\boxed{\boxed{ 0,2^{3} }}$



$b)\ (0,01)^{5} :(0,01)^{3} = 0,01^{5-3} =\boxed{\boxed{ 0,01^{2} }}$



$c)\ 3^{2} +(3^{3}: 3^{2} )= 3^{2} + 3^{3-2} = 3^{2} + 3= 9+3 = \boxed{\boxed{12}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$