resolva aa equacoes
a) 18x-43=65
b) 32x-16=14-17x
c) 10y-5(1+y)=3(2y-2)-20
d ) x(x+4)+x(x+2)=2x''+12
Soluções para a tarefa
Respondido por
1
A) 18x = 65 + 43
18 x = 108
x = 108 / 18
x = 6
B) 32x+17x = 14+16
49x = 30
x = 30/49
C) 10y-5-5y= 6y-6-20
5y-5 = 6y-26
5y-6y=-26+5
-y=-21
y=21
D) x²+4x+x²+2x=2x²+12
2x²+6x=2x²+12
2x²-2x²+6x=12
6x=12
x = 12/6
x=2
18 x = 108
x = 108 / 18
x = 6
B) 32x+17x = 14+16
49x = 30
x = 30/49
C) 10y-5-5y= 6y-6-20
5y-5 = 6y-26
5y-6y=-26+5
-y=-21
y=21
D) x²+4x+x²+2x=2x²+12
2x²+6x=2x²+12
2x²-2x²+6x=12
6x=12
x = 12/6
x=2
malluayume:
*corrigindoo # b) 23x-16=14-17x
23x+17x =14+16
40x = 30
x = 30/40 .. simplificando por 10 x =3/4
ou seja, (30:10)/(40:10) = 3/4
Respondido por
1
a) 18x-43=65 ==. 18x = 65+43==> 18x = 108 ==> x = 6
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b) 32x-16=14-17x ==> 32x+17x=14+16 ==. 49x=30==. x = 30/49
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c) 10y-5(1+y)=3(2y-2)-20 ==> 10y-5 -5y = 6y- 6-20
10y-5y-6y = - 6-20 + 5 ==> -y = -21(-1) ==> y = 21
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d ) x(x+4)+x(x+2)=2x''+12
x²+4x+x²+2x=2x²+12 ==> x²+4x+x²+2x - 2x² = +12
6x = 12 ==> x = 6
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