Question

'resolva a seguinte inequacao em IR: x elevado a 2 -3x+2.0, a solucao encontrada e'

Answer 1

$x^2-3x+2>0$

a=1 b= -3 c= 2

DELTA

Δ $=b^2-4.a.c$
Δ $=(-3)^2-4.1.2$
Δ $=9-8$
Δ $=1$

BHASKARA

x = -b±√Δ/2a
x = -(-3)±√1/2.1
x = 3±1/2

$x'= \frac{3+1}{2}\\\\x'= \frac{4}{2}\\\\ x' = 2$

$x''= \frac{3-1}{2}\\\\x''= \frac{2}{2}\\\\ x'' = 1$

S = {x'=2 e x''=1}