Question

resolva a seguinte equação fracionaria do 2º grau: X²+$\frac{5x}{2} - \frac{3}{2} =0$

Answer 1

$\dfrac{2x^2 + 5x - 3}{2} = 0 \\ \\ \\ => 2x^2 + 5x - 3 = 0$
MMC = 2 

Resolvendo por Bháskara:

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=2, b=5, c=-3

Δ= b^2 - 4ac 
Δ= 5^2 - 4*2*-3
Δ= 25 + 24 
Δ= 49

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-5 \pm \sqrt{49}}{2*2} \\ \\ \\ x = \dfrac{-5 \pm 7}{4} \\ \\ \\ x' = \dfrac{-5 + 7}{4} \\ \\ \\ x' = \dfrac{2}{4} \\ \\ \\ x' = \dfrac{1}{2} \\ \\ \\ x'' = \dfrac{-5 - 7}{4} \\ \\ \\ x'' = \dfrac{-12}{4} \\ \\ \\ x' = -3$

S = {$\dfrac{1}{2} , - 3$}