Question

Resolva a seguinte equação de segundo grau: x^2+4x-5=0

Answer 1

Resposta:

Explicação passo-a-passo:

x²+4x-5=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+4x-5=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=4~e~c=-5\\\\\Delta=(b)^{2}-4(a)(c)=(4)^{2}-4(1)(-5)=16-(-20)=36\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(4)-\sqrt{36}}{2(1)}=\frac{-4-6}{2}=\frac{-10}{2}=-5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(4)+\sqrt{36}}{2(1)}=\frac{-4+6}{2}=\frac{2}{2}=1\\\\S=\{-5,~1\}$