Question

Resolva a seguinte equação (8/125)^2x-1 = 1

Alguém pode me ajudar?

Answer 1

$\left( \dfrac{8}{125}\right)^{2x-1}=1\\\\ \left( \dfrac{8}{125} \right)^{2x-1}= \dfrac{8}{125}^0\\\\ 2x-1=0\\ 2x=1\\\\ x=1/2\\\\\\ \text{S}=\left\{ \dfrac{1}{2}\right\}$