Question

Resolva

A) Log2 ( 3x - 4) = 5
B) logx + log(x+3)= 1

Answer 1

$a) \\ log_2(3x-4)=5 \rightarrow 3x-4=2^5 \rightarrow 3x=32+4 \rightarrow x=\frac{36}{3}=12\\ \\ b)\\ logx+log(x+3)=1\\ \\ logx(x+3)=1\\ \\ x(x+3)=10^1\\ \\ x^2+3x-10=0\\ \\ \boxed{x=2}$