Question

Resolva a integral ∫((∛t)^2-2)dt ??

Answer 1

$\int {(\sqrt[3]{t})^2-2} \, dt= \\\\\\\int {t^{\frac23}-2} \, dt= \\\\\\\dfrac{t^{\frac23+1}}{\frac23+1}-2t+C=\\\\\\\dfrac{t^{\frac53}}{\frac53}-2t+C=\\\\\\\boxed{\dfrac35t\sqrt[3]{t^2}-2t+C}$