resolva a integral definida x(1+x³) dx no intervalo -1 até 2.
Soluções para a tarefa
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9
Olá Daiany
F(x) = ∫ x* (1 + x^3) dx = ∫ x + x^4 dx = x^2/2 + x^5/5 + C
F(2) = 4/2 + 32/5 = 42/5 = 84/10
F(-1) = 1/2 - 1/5 = 5/10 - 2/10 = 3/10
F(2) - F(-1) = 84/10 + 3/10 = 81/10
.
F(x) = ∫ x* (1 + x^3) dx = ∫ x + x^4 dx = x^2/2 + x^5/5 + C
F(2) = 4/2 + 32/5 = 42/5 = 84/10
F(-1) = 1/2 - 1/5 = 5/10 - 2/10 = 3/10
F(2) - F(-1) = 84/10 + 3/10 = 81/10
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Respondido por
9
∫x(x³ + 1)dx = ∫(x^4 + x)dx = _x^5_ + _x²_ (no intervalo de -1 à 2)
5 2
[_2^5_ - _(-1)^5_] + [ _2²_ - _(-1)²_ ]
5 5 2 2
[_33_] + [ _3_] = _66 + 15_ = _81_
5 2 10 10
5 2
[_2^5_ - _(-1)^5_] + [ _2²_ - _(-1)²_ ]
5 5 2 2
[_33_] + [ _3_] = _66 + 15_ = _81_
5 2 10 10
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