Question

Resolva a inequaçao quociente 2ײ+12×+10
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Answer 1

Resposta:

S = { x ∈ IR/ -5 < x < -1}

Explicação passo a passo:

2x² + 12x + 10 < 0

x² + 6x + 5 < 0

Raízes

x² + 6x + 5 = 0

Δ = b² - 4ac

Δ = 6² - 4.1.5

Δ = 36 - 20

Δ = 16

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-6\\\pm\sqrt{16} }{2.1}\\\\x=\frac{-6\pm4}{2} \\\\x=\frac{-10}{2}=-5\\ou\\x=\frac{-2}{2}=-1$

_____________-5.............................-1___________

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S = { x ∈ IR/ -5 < x < -1}