Question

Resolva a inequação: 2x² -5x+2>0

Answer 1

$2x^{2} -5x+2\ \textgreater \ 0 \\ (delta) = (-5^{2}) - 4.2.2 \\ (delta)= 25-16 \\ (delta) 9\ \textgreater \ 0$


$x = \frac{-(-5) +- \sqrt{9}}{2.2} \\ x= \frac{5+-3}{4} \\ x^{'}= 2\ \textgreater \ 0 \\ x^{''} = \frac{1}{2}\ \textgreater \ 0$

Answer 2

a=2 b=-5 c=2
delta=(-5)²-4*2*2
delta=25-16
delta=9

x=-(-5)±3/4
x=5±3/4=5+3/4=8/4=2
x=5-3/4=0,75

{x€R/2 ou 0,75>0}