Resolva a inequação 2x + 7 > 3x -3
Soluções para a tarefa
Respondido por
34
.
![2x+7\ \textgreater \ 3x-3 \\ \\ 2x-3x\ \textgreater \ -3-7 \\ \\ -x\ \textgreater \ -10 \\ \\ x\ \textless \ 10 2x+7\ \textgreater \ 3x-3 \\ \\ 2x-3x\ \textgreater \ -3-7 \\ \\ -x\ \textgreater \ -10 \\ \\ x\ \textless \ 10](https://tex.z-dn.net/?f=2x%2B7%5C+%5Ctextgreater+%5C+3x-3+%5C%5C++%5C%5C+2x-3x%5C+%5Ctextgreater+%5C+-3-7+%5C%5C++%5C%5C+-x%5C+%5Ctextgreater+%5C+-10+%5C%5C++%5C%5C+x%5C+%5Ctextless+%5C+10)
Respondido por
32
Oi Li,
só trocar o sinal de desigualdade quando x trocar o sinal..
![2x+7\ \textgreater \ 3x-3\\
2x-3x\ \textgreater \ -3-7\\
-x\ \textgreater \ -10\\
x\ \textless \ 10\\\\\\
\Large\boxed{\boxed{S=\{x\in\mathbb{R}~|~x\ \textless \ 10\}}} 2x+7\ \textgreater \ 3x-3\\
2x-3x\ \textgreater \ -3-7\\
-x\ \textgreater \ -10\\
x\ \textless \ 10\\\\\\
\Large\boxed{\boxed{S=\{x\in\mathbb{R}~|~x\ \textless \ 10\}}}](https://tex.z-dn.net/?f=2x%2B7%5C+%5Ctextgreater+%5C+3x-3%5C%5C%0A2x-3x%5C+%5Ctextgreater+%5C+-3-7%5C%5C%0A-x%5C+%5Ctextgreater+%5C+-10%5C%5C%0Ax%5C+%5Ctextless+%5C+10%5C%5C%5C%5C%5C%5C%0A%5CLarge%5Cboxed%7B%5Cboxed%7BS%3D%5C%7Bx%5Cin%5Cmathbb%7BR%7D%7E%7C%7Ex%5C+%5Ctextless+%5C+10%5C%7D%7D%7D)
Tenha ótimos estudos ;D
só trocar o sinal de desigualdade quando x trocar o sinal..
Tenha ótimos estudos ;D
Perguntas interessantes