Question

resolva a função: (2x-2)(2x+2)

Answer 1

$(2x - 2)(2x + 2) \\ 4x^{2} + 4x - 4x - 4 \\ {4x}^{2} - 4 = 0 \\ x = \frac{ - {b}^{2} + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ + - \sqrt{ - 4 \times 4 \times - 4} }{2 \times 4} \\ x = \frac{ + - \sqrt{64} }{8} \\ x = \frac{ + - 8}{8} \\ x = + - 1$