Question

Resolva a fórmula de bhaskara :

$x {}^{2} + x - 56 = 0$


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Answer 1

Δ = b²-4ac                   a = 1, b = 1 , c = -56

Δ = (1)² -4(1)(-56)

Δ = 1 -4(-56)

Δ = 1 + 224

Δ = 225

X = (-b±√Δ)/2a

X = (-1±√225)/2

X = (-1±15)/2

x' = (-1-15)/2 = -16/2 = -8

x'' = (-1 +15)/2 = 14/2 = 7

Espero ter ajudado ;)