Question

Resolva a fórmula de baskara

a) 3x2+4x+1=0

b) -x2+12x-20=0

Answer 1

Resposta:

Explicação passo a passo:

Resolva a fórmula de baskara

a) 3x^2+4x+1=0

"a=3; b =4; c =1"

∆= b²-4ac

∆= 4²-4.3.1

∆= 16-12

"∆= 4"

'x=[ - b+/- √∆]/2a'

'x=[-(-4)+/- √4]/2.3'

"x= (4+/- 2)/6"

" x'= (4+2)/6=6/6= 1"

' x " = (4-2)/6=2/6= 1/3 '

R.: S ={1 ; 1/3}

_________________

b) -x^2+12x-20=0 (-1)

"x²-12x+20=0"

a= 1; b = -12; c = 20

∆= b²-4ac

∆= (-12)² - 4.1.20

∆= 144-80

∆= 64

' x = (-b +/- √∆)/2a '

x=[-(-12)+/- √64]/2.1

' x = (12 +/- 8)'/2'

x' = (12+8)/2 = '20/2' = "10"

x" = (12-8)/2 = 4/2 = " 2 "

R.:s={2,10}