Question

Resolva a expressão...:, me ajudem a resolver?

Answer 1

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}\frac{ \left[\begin{array}{ccc}( \frac{1}{2})^3-( \frac{1}{4}-2) \end{array}\right] }{(0,666...-1)} \\\\ \frac{[ \frac{1}{8} - ( \frac{1-8}{4}) }{( \frac{2}{3}-1)\\\\ \frac{ \frac{1}{8}+ \frac{7}{4} }{ -\frac{1}{3} }\\\\ \frac{ \frac{1+14}{8} }{- \frac{1}{3} }\\\\ \boxed{\frac{15}{8}*-3 = - \frac{45}{8} =-5,625 }} \end{array}\right$

Espero ter ajudado. :))

Answer 2

$[( \frac{1}{2} ) ^{3} -( \frac{1}{4} - \frac{2}{} )]:( \frac{0,666...-1}{} )=$

$[ \frac{1}{8} -( \frac{1-8}{4} )]:( \frac{6}{9} - \frac{1}{} )=$

$[ \frac{1}{8} -( \frac{-7}{4} )]:( \frac{6-9}{9} )=$

$[ \frac{1}{8} + \frac{7}{4} ] : ( \frac{-3}{9} )=$

$[ \frac{1+14}{8} ] :( \frac{-3}{9} )=$

$\frac{15}{8} : (\frac{-3}{9} )=$

$\frac{15}{8} . ( \frac{-9}{3} )=$

=$= \frac{-135}{24} = -\frac{45}{8}$