Question

Resolva a expressão: 5x²-10x+9=1

Answer 1

$\mathtt{5x^2 -10x + 9 = 1 } \\ \mathtt{5x^2 -10x + 9 -1 = 0} \\ \mathtt{5x^2 -10x + 8 = 0} \\ \\ \mathtt{a = 5} \\ \mathtt{b = -10} \\ \mathtt{c = 8} \\ \\ \mathtt{\Delta = b^2-4\times a \times c} \\ \\ \mathtt{\Delta= (-10)^2 -4 \times 5 \times 8} \\ \mathtt{\Delta = 100 -20 \times 8} \\ \mathtt{\Delta = 100-160 } \\ \mathtt{\Delta = -60} \\ \\ \boxed{\mathtt{Por~\Delta~ser~menor~que~zero~n\~ao~existe~raiz~reais}}$

Answer 2

5x²-10x+9=1
5x²-10x+8=0

Δ=(-10)²-4 x 5 x 8 
Δ=100-160
Δ=-60

OU SEJA,NÃO TEM RAIZ (∉)