Question

resolva a expressão 3-[4+ (9²-5).(-2)]+ 1A)164B)-300C)-156D)156E)-164

Answer 1

3 - [4 + (9² - 5).(-2) ] + 1 = 

3 - [4 + (76).(-2) ] + 1 =

3 - [4 +(-152)] + 1=

3 - [4 - 152 ] + 1 =

3 - [ - 148 ] + 1 =

3 + 148 + 1 = 

152

Answer 2

=3-[4+ (9²-5).(-2)]+ 1
=3-[4+ (81-5).(-2)]+ 1
=3-[4+ 76.(-2)]+ 1
=3-[4-152]+ 1
=3-[-148]+ 1
=3+148+1
=152