Question

resolva a equação y2-4y+3=0

Answer 1

y² - 4y + 3 = 0

a = 1

b = -4

c = 3

Δ = (-4)² - 4.1.3

Δ = 16 - 12

Δ = 4

-b +- √Δ / 2.a

-(-4) +- √4 / 2.1

4 +- 2 / 2

x' = 4-2/2=2/2=1

x'' = 4+2/2=6/2=3