Question

resolva a equação √y² + 1 = 3

Answer 1

■ Se for √y² + 1 = 3  fica assim:

√y² + 1 = 3

√y² = 3 -1

√y² = 2

(√y²)² = 2² ⇔ y² = 4 ⇔ y = ±√4 ⇔ y = ±2 ⇔ S = {-2,2}

■ Se for  √(y² + 1) = 3  fica assim:

√(y² + 1) = 3 

[√(y² + 1)]² = 3² ⇔ y² + 1 = 9 ⇔ y² = 9 - 1 ⇔ y² = 8 ⇔ y = ±√8 ⇔

⇔ y = ±2√2 ⇔ S = {-2√2 , 2√2}

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05/03/2016 17:52:29
Sepauto - SSRC 
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