Question

resolva a equacao y=x ao quadrado - 6x+9=0,usando a forfula de bhaskara

Answer 1

$x^{2} -6x+9=0$

Δ = $b^2 - 4ac$

Δ = $6^2-4.1.9$

Δ = 36 - 36

Δ = 0

$\frac{-b + \sqrt{delta} }{2a}$

$\frac{-(-6)+0}{2.1}$

$\frac{6}{2} = 3$

S = {3}