Question

resolva a equacao x2+8x+16=0

Answer 1

x²+8x+16 = 0

a = 1

b = 8

c = 16

∆ = b²-4ac

∆ = 8²-4•1•16

∆ = 64 - 64

∆ = 0

$x \: = \: \frac{ - 8 + \sqrt{0} }{2}$

$x \: = \: \frac{ - 8}{2}$

$x = - 4$

$x = \frac{ - 8 - \sqrt{0} }{2}$

$x = \frac{ - 8 - 0}{2}$

$x = - 4$

As raízes são iguais, porque o discriminante (∆) é zero.