Question

Resolva a equação:
X²-20X+25=0

Answer 1

x²-20x+25=0

a=1 b= -20 c=25

∆=b²-4.a.c
∆=(-20)²-4.1.25
∆=400-100
∆=300

X= -b±√∆/2.a
X= -(-20)±√300/2.1
X= 20±√300/2

X'=20+√300/2=10+√300

X"=20-√300/2=10-√300

S={10-√300; 10+√300}

Answer 2

Use bascara( a fórmula de delta)