Question

resolva a equação x(ao quadrado)-5x+6=0

Answer 1

x² - 5x + 6 = 0

a = 1; b = -5; c = 6

Delta:
Δ = b² - 4ac
Δ = (-5)² - 4 * 1 * 6
Δ = 25 - 24
Δ = 1
        Bhaskara:
        x = - b ± √Δ / 2a
        x = - (-5) ± √1 / 2 * 1
        x = 5 ± 1 / 2
        x' = 5 + 1 / 2 = 6 / 2 = 3
        x'' = 5 - 1 / 2 = 4 / 2 = 2

S = {2, 3}

Espero ter ajudado. Valeu!

Answer 2

Determinando Delta
$a = 1 \\ b = -5 \\ c = 6 \\ \\ \Delta = b^{2} - 4ac \\ \Delta = (-5)^{2} - 4.1.6 \\ \Delta = 25 - 24 \\ \Delta = 1$

Determinando as raízes
$x = \frac{-b +- \sqrt{\Delta}}{2a} \\ x = \frac{-(-5) +- \sqrt{1}}{2.1} \\ x = \frac{5 +- 1}{2} \\ \\ x' = \frac{5 + 1}{2} \\ x' = \frac{6}{2} \\ x' = 3 \\ \\ x'' = \frac{5 - 1}{2} \\ x'' = \frac{4}{2} \\ x'' = 2$