Matemática, perguntado por andreiajpkpaqs7w, 11 meses atrás

resolva a equação X^6-3x^5+6x^3-3x^2-3x+2=0

Soluções para a tarefa

Respondido por walisoncdfzk
0
x^6 - 3x^5 + 6x^3 - 3x^2 - 3x + 2

>>--- 1 --- -3 --- 0 --- 6 --- -3 --- -3 --- 2
-1 --- 1 --- -4 --- 4 --- 2 --- -5 --- 2 --- 0 ----> x1 = -1 

x^5 -4x^4 + 4x^3 + 2x^2 -5x + 2
>>--- 1 --- -4 --- 4 --- 2 --- -5 --- 2
1 --- 1 --- -3 --- 1 --- 3 --- -2 --- 0 ----> x2 = 1 

x^4 -3x^3 + x^2 + 3x -2
>>--- 1 --- -3 --- 1 --- 3 --- -2
-1 --- 1 --- -4 --- 5 --- -2 --- 0 ----> x3 = -1 

x³ -4x² + 5x -2
>>--- 1 --- -4 --- 5 --- -2
1 --- 1 --- -3 --- 2 --- 0 ----> x4 = 1

x² -3x + 2 = 0
x5 = 1 e x6 = 2 

Logo a equação possui: uma raiz simples (x = 2), uma raiz dupla (x = -1) e uma raiz tripla (x = 1)
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