Question

resolva a equação√x+2+x=10

Answer 1

Resposta:

$x'=\frac{17+\sqrt{33} }{2} \\x"=\frac{17-\sqrt{33} }{2}$

Explicação passo-a-passo:

$\sqrt{x} +2+x=10\\\sqrt{x} +x=10-2\\\sqrt{x}+x=8\\\sqrt{x} =8-x\\(\sqrt{x})^2 =(8-x)^2\\x=64-16x+x^2\\x^2-16x-x+64=0\\x^2-17x+64=0\\\Delta=b^2-4*a*c\\\Delta=33\\\\x=\frac{-b_-^{+}\sqrt{\Delta} }{2*a}=\\\\x'=\frac{17+\sqrt{33} }{2} \\x"=\frac{17-\sqrt{33} }{2}$