Question

resolva a equaçao

|x^2+2x|=3

Answer 1

Resposta:

|x²+2x|=3

(x²+2x)=3

x²+2x=3

x²+2x-3=0

Δ= b²-4ac

Δ= 2²-4.1.(-3)

Δ=4+12

Δ= 16

x=-b±√Δ/2a

x= -2±√16/2.1

x= -2±4/2

x'= -2+4/2

x'= 2/2

x'= 1

x''= -2-4/2

x''= -6/2

x''= -3

s={1, -3}

Explicação passo-a-passo: