Question

resolva a equação x(1-x)=1/4 usando a fórmula bháskara​
ME AJUDA PFVR

Answer 1

$x(1 - x) = \frac{1}{4} \\ 1x - {x}^{2} = \frac{1}{4} \\ \frac{4x - 4 {x}^{2} }{4} = \frac{1}{4} \\ 4x - 4 {x}^{2} = 1 \\ - 4 {x}^{2} + 4x - 1 = 0 \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} \\ x = \frac{ - ( + 4) + - \sqrt{ {4}^{2} - 4 \times ( - 4) \times ( - 1) } }{2 \times ( - 4)} \\ x = \frac{ - 4 + - \sqrt{16 - 16} }{ - 8} \\ x = \frac{ - 4 + - 0}{ - 8} \\ x = \frac{ - 4}{ - 8} = \frac{1}{2}$