Question

resolva a equação (Utilizando a Formula de Bháskara):
25x²=20x - 4

Answer 1

Resposta:

25x² = 20x - 4

25x² - 20x + 4 = 0

Δ = b² - 4.a.c

Δ = (-20)² - 4.25.4

Δ = 400 - 400

Δ = 0

x = (-b ± √Δ)/2.a

x = (20 ± 0)/50

x' = 20/50 = 2/5

x" = 20/50 = 2/5

Answer 2

Oi

25x² -20x +4=0

a) = 25

b = - 20

c = 4

1) Achando Delta

Δ = b2 - 4.a.c

Δ = -202 - 4 . 25 . 4

Δ = 400 - 4. 25 . 4

Δ = 0

Há 1 raiz real.

2) Aplicando Bhaskara:

Neste caso, x' = x'':

x = (-b +- √Δ)/2a

x' = - (-20 + √0)/2.25

x' = 20 / 50 ÷ 10

x' = 2/5

x'' = -(-20 -√0)/2.25

x'' = 20 / 50 ÷ 10

x'' = 2/5

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