Question

Resolva a equação usando a formula de bhaskara 3x ao quadrado -10x+3=0?

Answer 1

3x² - 10x + 3 = 0

$x=-b~\pm~\dfrac{\sqrt{b^{2}-4~\cdot~a~\cdot~c}}{2~\cdot~a}}}\\\\\\\\\\ x = 10~\pm~\dfrac{\sqrt{(-10)^{2} -4~\cdot~3~\cdot~3}}{2~\cdot~3}}\\\\\\\\\\ x = 10~\pm~\dfrac{\sqrt{100-36}}{6}}\\\\\\\\\ x= 10~\pm~\dfrac{\sqrt{64}{6}}\\\\\\\\\ x = 10~\pm~\dfrac{8}{6}\\\\\\\\\ x' = \dfrac{10 + 8}{6}}\\\\\\\ x' = \dfrac{18}{6}}\\\\\\\\ \large\boxed{\boxed{x' = 3.}}}}}}}}}}}}\\\\\\\\ x" = \dfrac{10 - 8}{6}}\\\\\\\ x" = \dfrac{2}{6}}\\\\\\\\\ \large\boxed{\boxed{\boxed{x" = \dfrac{1}{3}}}}}}}}}}}}}}}}$

Ou seja, x' = 3 e x" = Um terço. (1/3)

Espero que te ajude '-'

Answer 2

delta=(-10)^2 - 4.3.3
delta=100-36
delta=64

x=-(-10+-raiz64)/2.3
X = (10+-8)6

x' = (10+8)/6 = 3

x" = (10 - 8)/6 = 2/6 = 1/3