Question

Resolva a equação tg²x = 3, sabendo que 0< X< 2π

Answer 1

Vamos là.

tg²(x) = 3

tg(x) = √3  

x = πn + π/3

x1 = π/3

x2 = π + π/3 = 4π/3

tg(x) = -√3  

x = πn - π/3

x = 6π/3 - π/3

x3 = 2π - π/3 = 5π/3

x4 = π - π/3 = 2π/3

S = (π/3, 2π/3, 4π/3, 5π/3)