Question

Resolva a equação

$\sqrt{3x + 6} - 2 = x$

Answer 1

$\sqrt{3x+6} - 2=x \\\\\sqrt{3x+6}=x+2\\\\(\sqrt{3x+6})^{2}=(x+2)^{2}\\\\ 3x+6 = (x+2)(x+2)\\\\3x+6=x^{2}+4x+2^{2}\\\\3x+6=x^{2}+4x +4\\\\0=x^{2}+4x-3x+4-6\\\\0=x^{2}+x-2$Neste caso utilizaremos Bháskara:
Δ=b² - 4ac
Δ=1² - 4.1.(-2)
Δ=1 + 8
Δ=9

x' = (-1+√9)/(2*1) =(-1+3)/2 = 1
x'' = (-1-√9)/(2*1) =(-1-3)/2 = -2