Question

resolva a equação : $log\sqrt{7x+5} + \frac{1}{2} log(2x+7)=1+\frac{9}{2}$

Answer 1

$log\sqrt{7x+5} + \frac{1}{2} log(2x+7)=1+\frac{9}{2} \: \\ log\sqrt{7x+5} + log\sqrt{(2x+7)}=\frac{11}{2} \\ log(\sqrt{7x+5})(\sqrt{2x+7})=\frac{11}{2} \\ \sqrt{7x+5} \times \sqrt{2x+7} = {10}^{ \frac{11}{2} } \\ (7x + 5)(2x + 7) = {10}^{11} \\ 7 {x}^{2} + 59x + 35 - {10}^{11} = 0$