Question

Resolva a equação $\left[\begin{array}{ccc}2&x-2&1\\1&x+3&4\\3&x+1&5\end{array}\right] = 56$

Answer 1

$\left[\begin{array}{ccc}2&(x-2)&1\\1&(x+3)&4\\3&(x+1)&5\end{array}\right] \begin{array}{ccc}2&(x-2)&\\1&(x+3)&\\3&(x+1)&\end{array} = 56$


$\text{da esquerda pra dirieta}\\2*(x+3)5+(x-2)*4*3+1*1*(x+1)\\\\10x+30 +12x-24+x+1\\\\23x+7\\\\\\\text{da direita pra esquerda }\\(x-2)*1*5+2*4*(x+1)+1*(x+3)*3\\\\5x-10+8x+8+3x+9\\\\16x+7$

resolvendo
$23x+7-(16x+7)=56\\\\23x+7-16x-7=56\\\\7x=56\\\\x= \frac{56}{7}$

Answer 2

Olá

Resolvendo temos.

{[2.(x+3).5+(x-2).4.3+1.1.(x+1)]- [1.(x+3).3 +4.(x+1).2+5.1.(x-2) ]}=56
{[10(x+3)+12(x-2)+(x+1)] -  [3(x+3)+8(x+1)+5(x-2)]}=56
{[10x+30+12x-24+x+1] -  [ 3x+9+8x+8+5x-10]}=56
{[ 23x+7] - [ 16x+7] }= 56
{23x+7-16x-7}=56
 7x=56
$x= \frac{56}{7} \\ \\ \boxed{x=8}$
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                                                 espero ter ajudado!!