Question

resolva a equação$4^ x^{2}^ +^4^x^=4^{12}$

Answer 1

$4^{x^{2}+4x}= 4^{12} \\ \\ 4^{x^{2}}.4^{4x}= 4^{12} \\ \\ a = 4^{x} \\ \\ a^{2}.a^{4} = 4^{12} \\ \\ a^{6}= 4^{12} \\ \\ \sqrt[6]{a^{6}}= \sqrt[6]{4^{12}} \\ \\ a = 4^{2} \\ \\ a = 4^{x} \\ 4^{2}= 4^{x} \\ x = 2$

Resposta: x = 2

Espero ter ajudado