Matemática, perguntado por NayRodrigues233, 1 ano atrás

Resolva a equação sendo ax^2 +c =0
4x^2 -64=0
X^2-1=0
25x^2-1 =0
49-16x^2=0

Soluções para a tarefa

Respondido por KarineFernandes83
1

4x² -64 = 0

(2x - 8) . (2x + 8) =0

2x - 8 = 0                  ou            2x + 8 = 0

2x = 8                                         2x = -8

x = 4                                            x = -4


S={4;-4}


X² - 1 = 0

(x -1). (x+ 1) = 0


x-1 = 0                      ou                        x + 1 = 0

x = 1                                                       x = -1


S={1;-1}


25x² -1 = 0

(5x -1) . (5x + 1) =0


5x -1 = 0                       ou                    5x + 1= 0

5x = 1                                                       5x =-1

x = 1/5                                                         x = -1/5


S={1/5; -1/5}


49 - 16x² = 0

(7 - 4x) . (7 + 4x) = 0


7 - 4x =0                     ou                           7 + 4x = 0

-4x = -7                                                       4x = -7

4x = 7                                                           x = -(7/4)

x = 7/4                                                          x = -7/4


S={7/4; - 7/4}

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