Question

Resolva a equação

SEN X= RAIZ DE 3/2, SENDO V =[0.2 pi]

Answer 1

senx = √3/2 => x = π/3 + 2kπ
ou
x = (π - π/3) + 2kπ

x = (3π - π)/3 + 2kπ

x = 2π/3 + 2kπ

S = { x ∈ IR/ x = π/3 + 2kπ ou x = 2π/3 + 2kπ, k ∈ Z }