Question

resolva a equação logarítmica logx2(x²-5x+10)=2​

Answer 1

Resposta:

logx2(x²-5x+10)=2​

logx2(x²-5x+10)=logx2​

x²-5x+10 = 2

x²-5x+10-2 = 0

x²-5x+8 = 0

$x=\frac{5+-\sqrt{(-5)^{2}-4*1*8 } }{2} \\\\x=\frac{5+-\sqrt{25-32 } }{2} \\\\x=\frac{5+-\sqrt{-7 } }{2} \\\\x=\frac{5+\sqrt{-7 } }{2} \\ou\\x=\frac{5-\sqrt{-7 } }{2}$

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