Resolva a equação : log2(logx16)= 3
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Olá Annanda,
![\log_2(\log_x16)=3\\
\log_2(\log_x16)=\log_28\\
\log_x16=8\\\\
x^8=16\\
x=\pm \sqrt[8]{16}\\x=\pm \sqrt[8]{2^4}\\
x=\pm \sqrt{2}\\\\
x= \sqrt{2}~~e~~- \sqrt{2}~(n\~ao~atende)\\\\\\
x= \sqrt{2}](https://tex.z-dn.net/?f=%5Clog_2%28%5Clog_x16%29%3D3%5C%5C%0A%5Clog_2%28%5Clog_x16%29%3D%5Clog_28%5C%5C%0A%5Clog_x16%3D8%5C%5C%5C%5C%0Ax%5E8%3D16%5C%5C%0Ax%3D%5Cpm+%5Csqrt%5B8%5D%7B16%7D%5C%5Cx%3D%5Cpm+%5Csqrt%5B8%5D%7B2%5E4%7D%5C%5C%0Ax%3D%5Cpm+%5Csqrt%7B2%7D%5C%5C%5C%5C%0Ax%3D+%5Csqrt%7B2%7D%7E%7Ee%7E%7E-+%5Csqrt%7B2%7D%7E%28n%5C%7Eao%7Eatende%29%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Csqrt%7B2%7D++++++ "\log_2(\log_x16)=3\\
\log_2(\log_x16)=\log_28\\
\log_x16=8\\\\
x^8=16\\
x=\pm \sqrt[8]{16}\\x=\pm \sqrt[8]{2^4}\\
x=\pm \sqrt{2}\\\\
x= \sqrt{2}~~e~~- \sqrt{2}~(n\~ao~atende)\\\\\\
x= \sqrt{2}")
Tenha ótimos estudos ^^
Tenha ótimos estudos ^^
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