Question

Resolva a equação:
Log (x^2 -4x + 4) = 0 na base 2

Answer 1

Log2 (x^2 -4x + 4) = 0

(x^2 -4x + 4) = 2^0

x² - 4x + 4 = 1

x² - 4x + 3 = 0
∆= 16 - 12= 4 ==> √∆=2
x' = 4+2/2 = 3 ✓
x" = 4-2/2 = 1 ✓