Question

Resolva a equação literal :
x²- 2tx + t² = 0

Answer 1

x² - 2 t x + t² = 0
a = 1
b = - 2 t
c = t²
Δ = b² - 4 .a . c
Δ = (- 2 t)² - 4 .1 . t²
Δ= 4 t²  - 4 t²
Δ = 0
\/¨0 = 0
x = -b /2 .1
x´= x" =- ( -2 t )/2
x´=x" = 2 t /2 cancela t fica
x´= x" = 2