Question

Resolva a equação literal, sendo x a incógnita:

-mx²+5x=0

Answer 1

mx²-5x=0

x(mx-5)=0
x'=0
mx-5=0
mx=5
x"=5/m

S={0,5/m} com m≠0

mx²-5x=0
Δ=25

$x'= \frac{5-5}{2m}= \frac{0}{m}0$

x"=$\frac{5+5}{2m} = \frac{10}{2m} = \frac{5}{m}$

S={$0, \frac{5}{m}$}  com m≠0